C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 7)
7.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char *str;
str = "%s";
printf(str, "K\n");
return 0;
}
Discussion:
57 comments Page 3 of 6.
Kartik said:
1 decade ago
Why is the need for this kind of format: printf ("%s", "hello").
If we can simply print using: printf ("hello") ;.
TAKE A MOMENT Please!
If we can simply print using: printf ("hello") ;.
TAKE A MOMENT Please!
Assasin said:
1 decade ago
#include<stdio.h>
#include<conio.h>
int main()
{
printf("hi","bye");
}
please explain this output: hi.
#include<conio.h>
int main()
{
printf("hi","bye");
}
please explain this output: hi.
Nithiya said:
1 decade ago
int main()
{
int *str;
str = "%d";
printf(str, "5\n");
return 0;
}
What will be the output?
{
int *str;
str = "%d";
printf(str, "5\n");
return 0;
}
What will be the output?
Rahul said:
1 decade ago
str will store address of variable if and only if variable is preceded by &
otherwise it will store value of variable.
otherwise it will store value of variable.
Omkar said:
1 decade ago
@Ravi.
Your code is working, its working because printf function needs one fixed argument and n variable arguments.
Your code is working, its working because printf function needs one fixed argument and n variable arguments.
Sree said:
1 decade ago
Hai kavyashree.
Printf ("%s", "k\n") ; why %s is not shown as output which in double quotes. Only k as output.
Printf ("%s", "k\n") ; why %s is not shown as output which in double quotes. Only k as output.
Prakash said:
5 months ago
There is no format specifier in print statement. So it doesn't print the structure value it only prints the K.
Shahin said:
1 decade ago
So, can we assign a format specifier to the variable ? If so, the above solution will be correct explain me?
Sandeep(MCA) said:
1 decade ago
It will print k because we don't add the %c with str. So it will print only massage which is in "".
Abu zaid said:
10 years ago
%s is the format specifier type of string.
We can declare it anywhere in the local scope.
We can declare it anywhere in the local scope.
(2)
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