C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 7)
7.
What will be the output of the program ?
#include<stdio.h>
int main()
{
char *str;
str = "%s";
printf(str, "K\n");
return 0;
}
Discussion:
57 comments Page 2 of 6.
Abu zaid said:
10 years ago
%s is the format specifier type of string.
We can declare it anywhere in the local scope.
We can declare it anywhere in the local scope.
(2)
Mohit said:
10 years ago
Change %s with %c, %x. You will see that str is replace by different output.
(2)
Mitali said:
10 years ago
@Shahin.
How it will give garbage value as an output?
How it will give garbage value as an output?
Shahin said:
1 decade ago
@Nithiya.
The output will be garbage value.
The output will be garbage value.
Shahin said:
1 decade ago
So, can we assign a format specifier to the variable ? If so, the above solution will be correct explain me?
Nithiya said:
1 decade ago
int main()
{
int *str;
str = "%d";
printf(str, "5\n");
return 0;
}
What will be the output?
{
int *str;
str = "%d";
printf(str, "5\n");
return 0;
}
What will be the output?
Amir Khan said:
1 decade ago
Can anyone explain me this:
If,
int *str="abcd"
Then first character will be 'a' not '"'(Double quotes).
Then, if we initialize as,
str = "%s";
printf(str, "K\n");
Then printf requires "--"(double quotes).
And if we replace str value in printf function, then it will write as,
printf(%s,"K\n");
Got my point everybody? Please reply me.
If,
int *str="abcd"
Then first character will be 'a' not '"'(Double quotes).
Then, if we initialize as,
str = "%s";
printf(str, "K\n");
Then printf requires "--"(double quotes).
And if we replace str value in printf function, then it will write as,
printf(%s,"K\n");
Got my point everybody? Please reply me.
(2)
Bhavin said:
1 decade ago
What we write in double quotes will get printed simple?
Assasin said:
1 decade ago
#include<stdio.h>
#include<conio.h>
int main()
{
printf("hi","bye");
}
please explain this output: hi.
#include<conio.h>
int main()
{
printf("hi","bye");
}
please explain this output: hi.
Singh is king said:
1 decade ago
Based on the total var we need to specify scope identifiers.
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