C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 6)
6.
What will be the output of the program ?
#include<stdio.h>
void fun(void *p);
int i;
int main()
{
void *vptr;
vptr = &i;
fun(vptr);
return 0;
}
void fun(void *p)
{
int **q;
q = (int**)&p;
printf("%d\n", **q);
}
Discussion:
95 comments Page 6 of 10.
Sravanthi said:
1 decade ago
I didn't understand where variable i is declared as extern can any one tell me?
Sunil said:
1 decade ago
i is declare as global variable & default value of global variable is 0.
Abhishek shrivastava said:
1 decade ago
Because I is declared as extern, and external variable always will have 0;.
Aneesha said:
1 decade ago
Uninitialized static and extern(global) varibles are by default set to 0.
Kowsik said:
8 years ago
What will be output of program if 'i' is initialised globally as int i=5?
PRASHANT SISODIYA said:
10 years ago
Any one tell me why void not convert to int A option is not the answer?
Mohamed mohsen said:
1 decade ago
Because i is global variable by default compiler initialize it to zero.
Seema said:
1 decade ago
As i is declared global and default value of global variables is 0.
Prasun said:
1 decade ago
By default the global variable has default value 0. So answer is 0.
Venky said:
1 decade ago
@Geetha void function () means the function returns nothing not 0.
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