C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 6)
6.
What will be the output of the program ?
#include<stdio.h>
void fun(void *p);
int i;
int main()
{
void *vptr;
vptr = &i;
fun(vptr);
return 0;
}
void fun(void *p)
{
int **q;
q = (int**)&p;
printf("%d\n", **q);
}
Discussion:
95 comments Page 5 of 10.
Nandkishor said:
10 years ago
int i; is declare as external. Hence for external storage class default value is 0. That is the reason why it prints 0.
Ashish said:
1 decade ago
That's because I is declared as a global and and not been initialized. Default value of global variable is 0.
Venky said:
1 decade ago
@Geetha void function () means the function returns nothing not 0.
Viki said:
1 decade ago
Does void pointer returns zero?
Mahi khan said:
1 decade ago
How 0 is output and what is the use of int**?
Geetha said:
1 decade ago
void methods always returns zero I think:).
Prasun said:
1 decade ago
By default the global variable has default value 0. So answer is 0.
Mohamed mohsen said:
1 decade ago
Because i is global variable by default compiler initialize it to zero.
Manoj & Vinay said:
1 decade ago
Actually void pointer always needs to be casted whenevr we perform any operation on it.
q = (int**)&p;
Here void ptr is casted into integer ptr.
q = (int**)&p;
Here void ptr is casted into integer ptr.
Sravanthi said:
1 decade ago
I didn't understand where variable i is declared as extern can any one tell me?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers