C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 10)
10.
What will be the output of the program ?
#include<stdio.h>
int main()
{
void *vp;
char ch=74, *cp="JACK";
int j=65;
vp=&ch;
printf("%c", *(char*)vp);
vp=&j;
printf("%c", *(int*)vp);
vp=cp;
printf("%s", (char*)vp+2);
return 0;
}
Discussion:
84 comments Page 9 of 9.
Chinni said:
1 decade ago
Thanks a lot... dude.
Ganesh said:
1 decade ago
Thanks Nilesh nice explanation.
Preethi said:
1 decade ago
Thanks Nilesh.
Nilesh said:
1 decade ago
Pointer always store integer value so cp will store the memory address of location where string "jack " is stored.
Step 1 : vp = &ch;
/*Will store address of ch in vp so while we print content in printf it will print asccii value of 74 i.e "J"*/
Step 2 : vp = &j;
/* It will assign address of j to vp again it will print ascii value of 65 as "A"*/
Step 3 : vp = cp;
/* In this step cp is pointing to memory locatioon where string jack is stored and we r incrementing it by two so it will point to "C" from sring "JACK" and since we hava given %S in printf so it will print content from c onwords ie "CK"*/
So final combined output will be JACK.
Step 1 : vp = &ch;
/*Will store address of ch in vp so while we print content in printf it will print asccii value of 74 i.e "J"*/
Step 2 : vp = &j;
/* It will assign address of j to vp again it will print ascii value of 65 as "A"*/
Step 3 : vp = cp;
/* In this step cp is pointing to memory locatioon where string jack is stored and we r incrementing it by two so it will point to "C" from sring "JACK" and since we hava given %S in printf so it will print content from c onwords ie "CK"*/
So final combined output will be JACK.
(47)
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