C Programming - Pointers - Discussion

Discussion Forum : Pointers - Find Output of Program (Q.No. 15)
15.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    printf("%c\n", 7["IndiaBIX"]);
    return 0;
}
Error: in printf
Nothing will print
print "X" of IndiaBIX
print "7"
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
43 comments Page 4 of 5.

Sanketrjain said:   1 decade ago
Thanks raghu and shamini.

Raghu said:   1 decade ago
It is just trick of mathematics. a[3] = 3[a] --> they are commutative both are expanded by compiler as *(a+3) and *(3+a) respectively. Even you can assign a variable to 3[a] = "X" which is same as a[3]="X".

Venky said:   1 decade ago
Actually: num[i]<=>*(num+i)<=>*(i+num)<=>i[num]

So 7 is index and indiabix is string. Thus X of indiabix.

Rajutaya@gmail.com said:   1 decade ago
Ya correct guys, if it is printf("%d",7[indiabiA]);
means it will print the integer values as A=65

Arvind said:   1 decade ago
Thnx wikiok.

Wikiok said:   1 decade ago
myarray[5] == 5[myarray]

Manoj said:   1 decade ago
Hey program is good, because whenever complier can't define any data type or user define %c means char or you can modify this program or define %f,
%d then you will get satisfied answer.

UmU said:   1 decade ago
@narender no you are wrong.

@samini good thnx. :).

Narendra said:   1 decade ago
I think when we write like that then compiler will skip first 6 letters &then print remaining.

Gopi said:   1 decade ago
Good. Thank you.


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