C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 15)
15.
What will be the output of the program ?
#include<stdio.h>
int main()
{
printf("%c\n", 7["IndiaBIX"]);
return 0;
}
Discussion:
43 comments Page 3 of 5.
Kishanth said:
7 years ago
Thank you all for explaining it.
Aju said:
7 years ago
@Bins Emmanuel.
Nice explanation, Thanks.
Nice explanation, Thanks.
Raghu said:
1 decade ago
It is just trick of mathematics. a[3] = 3[a] --> they are commutative both are expanded by compiler as *(a+3) and *(3+a) respectively. Even you can assign a variable to 3[a] = "X" which is same as a[3]="X".
Shamini said:
2 decades ago
printf("%c\n", 7["IndiaBIX"]);
It is printing the 7th character of the string "IndiaBIX".
I-0,
n-1,
d-2,
i-3,
a-4,
B-5,
I-6,
X-7.
Sathya said:
2 decades ago
Thanks Shamini.
Gopi said:
1 decade ago
Good. Thank you.
Narendra said:
1 decade ago
I think when we write like that then compiler will skip first 6 letters &then print remaining.
UmU said:
1 decade ago
@narender no you are wrong.
@samini good thnx. :).
@samini good thnx. :).
Manoj said:
1 decade ago
Hey program is good, because whenever complier can't define any data type or user define %c means char or you can modify this program or define %f,
%d then you will get satisfied answer.
%d then you will get satisfied answer.
Wikiok said:
1 decade ago
myarray[5] == 5[myarray]
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