C Programming - Pointers - Discussion
Discussion Forum : Pointers - Find Output of Program (Q.No. 13)
13.
What will be the output of the program?
#include<stdio.h>
int main()
{
int arr[3] = {2, 3, 4};
char *p;
p = arr;
p = (char*)((int*)(p));
printf("%d, ", *p);
p = (int*)(p+1);
printf("%d", *p);
return 0;
}
Discussion:
87 comments Page 9 of 9.
Sai said:
1 decade ago
Please explain about
p = (int*)(p+1);
printf("%d", *p);
p = (int*)(p+1);
printf("%d", *p);
Prateek said:
1 decade ago
p is a char. pointer and it is assigned to complete address of arr array. so when we write (ar+1) it take address next beyond arr array. which having value 0 of defined pointer array.
Sundar said:
2 decades ago
The char pointer only stores the first byte address of integer. So while increment the pointer the next value is to be printed as 0.
Rajadurai said:
2 decades ago
The answer is correct. We can convert int pointer to char pointer and viz versa. *p is apoint to first variable. *p+1 points the next array, so the answer is zero.
DRukus said:
2 decades ago
p is declared as a char pointer but arr is an integer array
the assignment p = arr produces a compile-time error.
the assignment p = arr produces a compile-time error.
Ravi said:
2 decades ago
p=arr;//here p is a character pointer. we should not assign int array base address...
Badareenath said:
2 decades ago
Can anybody explain this please ?
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