C Programming - Pointers - Discussion
Discussion Forum : Pointers - General Questions (Q.No. 6)
6.
What would be the equivalent pointer expression for referring the array element a[i][j][k][l]
Discussion:
70 comments Page 7 of 7.
Rishabh said:
1 decade ago
An another way to represent pointer as array is ?
ptr[0]------>*(ptr+0);
ptr[1]------>*(ptr+1);
ptr[0]------>*(ptr+0);
ptr[1]------>*(ptr+1);
Ravitheja said:
1 decade ago
Anil Kumar Kandula.
Thank you very much. Nice eplanation.
Thank you very much. Nice eplanation.
Mark said:
1 decade ago
Please, someone clear my doubt.
main()
{
int a[2][2]={1,2,3,4};
printf("%d %d",a+1,*(a+1));
}
In this problem both values of printf are same.. how could it.. if a+1 denotes address of a[1][0], then *(a+1) should display its value, but why not..??? please explain ?
main()
{
int a[2][2]={1,2,3,4};
printf("%d %d",a+1,*(a+1));
}
In this problem both values of printf are same.. how could it.. if a+1 denotes address of a[1][0], then *(a+1) should display its value, but why not..??? please explain ?
Rajesh said:
1 decade ago
Nice Explanation by ramaji & pradeep.
Sagar said:
1 decade ago
Thanks pradeep
Meenu said:
1 decade ago
Explain this concept.
Ashok said:
1 decade ago
Given: a[i][j][k][l]
i number of rows with
{
each contains j number of rows with
{
each contains k number of rows with
{
EACH CONTAINS l no of columns
}
}
}
i number of rows with
{
each contains j number of rows with
{
each contains k number of rows with
{
EACH CONTAINS l no of columns
}
}
}
Bhuvana said:
1 decade ago
Thanks ramanji.
Kuttu said:
1 decade ago
Thanks anil kumar.
Anil kumar Kandula said:
1 decade ago
a[i] = *(a+i)
a[i][j] = *(a[i]+j)
= *(*(a+i)+j)
a[i][j][k]= *(a[i][j]+k)
= *(*(a[i]+j)+k)
= *(*(*(a+i)+j)+k)
a[i][j] = *(a[i]+j)
= *(*(a+i)+j)
a[i][j][k]= *(a[i][j]+k)
= *(*(a[i]+j)+k)
= *(*(*(a+i)+j)+k)
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