C Programming - Pointers - Discussion
Discussion Forum : Pointers - General Questions (Q.No. 2)
2.
Can you combine the following two statements into one?
char *p;
p = (char*) malloc(100);
Discussion:
82 comments Page 3 of 9.
Sivakumar said:
1 decade ago
#include<stdio.h>
int main(){
int i=320;
char *ptr=(char*)&i;
printf("%d",*ptr);
return 0;
}
Ans: 64.
Could anyone explain this program and answer?.
int main(){
int i=320;
char *ptr=(char*)&i;
printf("%d",*ptr);
return 0;
}
Ans: 64.
Could anyone explain this program and answer?.
Vij said:
1 decade ago
1. char p;
p= (char *) malloc (1000) ;
2. char *p;
p= (char *) malloc (1000) ;
Is that 1 and 2 mean the same. explain?
p= (char *) malloc (1000) ;
2. char *p;
p= (char *) malloc (1000) ;
Is that 1 and 2 mean the same. explain?
Praphulla said:
1 decade ago
malloc & calloc both are memory allocation function & both returns void type where afterwords we type case it.
ex:
int *p;
p=(int*)malloc(1000);
where malloc depends upon byte which are fixed i.e 8-bit,again 16-bit.
calloc deals with no.of bytes where bytes is considered as block relevant to the memory issue.
ex:
int *p;
p=(int*)malloc(1000);
where malloc depends upon byte which are fixed i.e 8-bit,again 16-bit.
calloc deals with no.of bytes where bytes is considered as block relevant to the memory issue.
Shubham Arora said:
1 decade ago
I want to explain brief discription about the char that char represents a individual value during coding in c language i.e. p in above code,as we can also write as char p = malloc(100);
Rishi said:
9 years ago
Explanations are good.
But one think is missing that since *p points to the beginning address, thus p=char* malloc(100), can be assigned with a char*p.
The type should be same is the necessary point but why so works is because of p(base address).
But one think is missing that since *p points to the beginning address, thus p=char* malloc(100), can be assigned with a char*p.
The type should be same is the necessary point but why so works is because of p(base address).
Parth lathiya said:
3 years ago
@Vij.
Both are not the same.
Because
1) not a proper variable pointer declaration.
So, 2) proper define the pointer variable.
Both are not the same.
Because
1) not a proper variable pointer declaration.
So, 2) proper define the pointer variable.
Vijay said:
8 years ago
step 1: char p // It is normal.
step 2: here we are using pointer so p = p* and p = 1000(size).
step 3 : P* = (char*)malloc(1000).
step 2: here we are using pointer so p = p* and p = 1000(size).
step 3 : P* = (char*)malloc(1000).
Pooja said:
8 years ago
Not getting it, Explain it in detail.
Shehryar said:
8 years ago
Explain it in detail.
LOIS said:
9 years ago
In C, 0 = true and others values represent false; then when one return 0 is to say that no errors occur.
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