C Programming - Memory Allocation - Discussion
Discussion Forum : Memory Allocation - Find Output of Program (Q.No. 2)
2.
What will be the output of the program (16-bit platform)?
#include<stdio.h>
#include<stdlib.h>
int main()
{
int *p;
p = (int *)malloc(20);
printf("%d\n", sizeof(p));
free(p);
return 0;
}
Discussion:
31 comments Page 3 of 4.
Ruchita said:
10 years ago
sizeof(pointer) always returns size of pointer i.e size of address and it varies compiler to compiler.
char *ptr;
int *ptr;
float *ptr;
For all, sizeof(ptr) will be same, for 16 bit compiler its 2 bytes and for 32 its 4 bytes.
char *ptr;
int *ptr;
float *ptr;
For all, sizeof(ptr) will be same, for 16 bit compiler its 2 bytes and for 32 its 4 bytes.
Sarvajeet Suman said:
10 years ago
For GCC compiler it's 4 & not 2.
Muzammil said:
9 years ago
It depends on the compiler for Linux platform pointer size is 4 and in windows, it's 2.
Yash said:
8 years ago
@Vinay and @Raju Naidu are absolutely correct.
Prafull said:
8 years ago
I think in question it's already mentioned 16-bit so answer is 2.
Agree @Vinay & @Raju Naidu.
Agree @Vinay & @Raju Naidu.
Suraj said:
8 years ago
Answer is 4 because integer pointer is size is 4byte.
Rohit Sundaram said:
7 years ago
In 32-bit machine, the sizeof pointer is 32 bits (4 bytes) , while on a 64-bit machine it's 8 bytes. Regardless of what data type they are pointing to, they have fixed size.
Aniket potabatti said:
7 years ago
P is an integer pointer and it contains 2 bytes of memory so answer is 2.
Vijay kumar said:
6 years ago
The answer is 8 because the size of a pointer is always 8.
Sripadh said:
5 years ago
But if I run this program it is showing the output as 8.
(1)
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