C Programming - Library Functions - Discussion
Discussion Forum : Library Functions - Find Output of Program (Q.No. 2)
2.
What will be the output of the program?
#include<stdio.h>
#include<math.h>
int main()
{
float i = 2.5;
printf("%f, %d", floor(i), ceil(i));
return 0;
}
Answer: Option
Explanation:
Both ceil() and floor() return the integer found as a double.
floor(2.5) returns the largest integral value(round down) that is not greater than 2.5. So output is 2.000000.
ceil(2.5) returns 3, while converting the double to int it returns '0'.
So, the output is '2.000000, 0'.
Discussion:
18 comments Page 2 of 2.
DJV said:
1 decade ago
ceil(2.5) returns '3'.
As double is 8 bytes- 3 is represented as :
00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000011
So while converting double to int(which is of 4 bytes).
The first four bytes will be taken into consideration.
Hence returning the value '0' :).
As double is 8 bytes- 3 is represented as :
00000000 00000000 00000000 00000000 00000000 00000000 00000000 00000011
So while converting double to int(which is of 4 bytes).
The first four bytes will be taken into consideration.
Hence returning the value '0' :).
(5)
Ramya said:
1 decade ago
Ceil always return double value. But here return type is integer while converting double to integer 8 bytes is converted to 4 byte real value. So four bits from right to return zero.
(1)
Ganesh singh said:
1 decade ago
I have got the o/p=0; but now I am confused with the concept used in the following case given below:
int main()
{
double a=3;
int b=a;
printf("%d",b);
}
Please make me understood soon as possible.
int main()
{
double a=3;
int b=a;
printf("%d",b);
}
Please make me understood soon as possible.
Prince Rambade said:
1 decade ago
Ok if i assume above explanation to be correct. Then pls explain how below program result in,
Output : 0,0.00000000 ?
int main()
{
float i = 2.5;
printf("%d, %f", floor(i), ceil(i));
return 0;
}
ceil() returns a double & I have printed the value with %f format specifier but it results in 0.000000 how ?
Output : 0,0.00000000 ?
int main()
{
float i = 2.5;
printf("%d, %f", floor(i), ceil(i));
return 0;
}
ceil() returns a double & I have printed the value with %f format specifier but it results in 0.000000 how ?
Cvam singh said:
1 decade ago
Please specify that it will return from right or left.
Amarjeet said:
9 years ago
It prints 0 because doubles priority is higher than an integer.
That's why it prints 2.000000 and 0.
That's why it prints 2.000000 and 0.
Swapnil Kudale said:
8 years ago
@Djv is correct.
Rakhi Sinha said:
5 years ago
GCC compiler is giving some garbage value instead of 0.
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