C Programming - Input / Output - Discussion

Discussion Forum : Input / Output - Find Output of Program (Q.No. 10)
10.
What will be the output of the program ?
#include<stdio.h>

int main()
{
    printf("%%%%\n");
    return 0;
}
%%%%%
%%
No output
Error
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
36 comments Page 3 of 4.

Dheeraj said:   1 decade ago
Why printf("%??%%%%%\n"); giving output of %??%%% ?

Ranjitha said:   1 decade ago
@josna:

If we print %%% the result is % and not %%.

Pavani said:   1 decade ago
#include<stdio.h>
#include<conio.h>
main()
{
clrscr();
printf("%\n");//only one % is used
getch();
}
o/p:
%
Q:why it happened?

Narayan said:   1 decade ago
I don't get anyone answer. Can anyone please explain about :

1. printf("%%%\n") (what will be o/p).
2. printf("%%\n") (what will be o/p).
3. printf("%\n") (what will be o/p).

Give ans respectively with proper explanation.

Bhavesh jain said:   1 decade ago
printf("%\n")

It will give output % . and to print % in c we have to add \n or \t or \r ..so it will terminate the % which starts finding for the d,s,c,f char to print something. so if we give \t ,\n then it will stop finding and simply print %.

K Jagannadham said:   1 decade ago
We can print % in C.

But another way to print % we need %% in C.

But to print %% we need %%% or %%%% in C.

And next to print %%% we need %%%%% or %%%%%% in C.
And so on.....

Sunil said:   10 years ago
C is sea. If you want to find it will in deep.

Amit agarwal said:   9 years ago
Also, we can't print " " using simple printf (" " " ") ;.

Should we write printf ("\" " ") ;?

R.Monika said:   9 years ago
I want some more detail explanations! please help me friends.

Kamlesh Lohar said:   8 years ago
First % is take as identifier and next take as value that's why output is %%.

Because 1st taken as identifier and 2nd as value and just like 3rd taken as identifier and 4th as value.
(2)


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