C Programming - Functions - Discussion
Discussion Forum : Functions - General Questions (Q.No. 1)
1.
The keyword used to transfer control from a function back to the calling function is
Answer: Option
Explanation:
The keyword return is used to transfer control from a function back to the calling function.
Example:
#include<stdio.h>
int add(int, int); /* Function prototype */
int main()
{
int a = 4, b = 3, c;
c = add(a, b);
printf("c = %d\n", c);
return 0;
}
int add(int a, int b)
{
/* returns the value and control back to main() function */
return (a+b);
}
Output:
c = 7
Discussion:
35 comments Page 2 of 4.
Mahesh Kharvi said:
1 decade ago
0 is beside return because the function is integer type it should return integer value.
Tarun said:
1 decade ago
We cannot write two arguments in the return statements
ex:
return(x,y);
it will take only 3
ex:
return(x,y);
it will take only 3
Robot said:
1 decade ago
Tell me the difference between printf (predefined function) and return (keyword).
R@M said:
1 decade ago
Relation between main function and called function is called "PROTOTYPE".
EX:- int add(int, int); /* Function prototype */
EX:- int add(int, int); /* Function prototype */
Mahesh said:
1 decade ago
I think the answer is also may be relating to functions..
and finally what is the out put;
main(){
printf("Mahesh @ SVM");
main();
}
and finally what is the out put;
main(){
printf("Mahesh @ SVM");
main();
}
Vinny said:
1 decade ago
What is difference between goto, return, go back and switch?
Raji said:
1 decade ago
printf function can be used for print the statement and return keyword can be used for return the routine from called function to calling function declaration.
Vignesh said:
1 decade ago
Function prototyping is nothing but we are declaring that we have a function in a specific name to the compiler.
Keerthana said:
1 decade ago
What is notation?
Shiva kumar kella said:
1 decade ago
@Ritika.
Answer is 1 and 1 and 3.
Explanation is :
Here is we have a command on post and pre increments.
Post increment :
1. First print the given number, and
2. Now increment itself by 1.
Pre increment :
1. First increment it self by 1, and
2. Now it's print what it have.
So ans ;1.a=1=> printed 1;
a++ => here printed 1 and incremented it self by 1 i.e. a=2;
++a => printed 3, because before a printing a will incremented by 1 ;
Answer is 1 and 1 and 3.
Explanation is :
Here is we have a command on post and pre increments.
Post increment :
1. First print the given number, and
2. Now increment itself by 1.
Pre increment :
1. First increment it self by 1, and
2. Now it's print what it have.
So ans ;1.a=1=> printed 1;
a++ => here printed 1 and incremented it self by 1 i.e. a=2;
++a => printed 3, because before a printing a will incremented by 1 ;
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