C Programming - Functions - Discussion

Please any one can explain me clearly.

@Vasuroshan, thank you for your explaination.

if (a=b), i.e if both values are equal, then it returns 0;
if (a<b), i.e if a is less than b, then it returns -1;
if (a>b), i.e if a is greater than b, then it returns 1;

Thanks vishwas.

Excellent answer!!Vishwas

Thank you vishwas.

Simple:
The return statement in proc function is replaced like this:
return( fun(a,b));
Which means calling the function fun(a,b).
Since it returns a==b and integer value of true is 1, the output is 1.

@Ashish.

#include<stdio.h>
int fun(int);
typedef int (*pf) (int, int);
int proc(pf, int, int);

int main()
{
printf("%d\n", proc(fun, 6,6));
return 0;
}
int fun(int a)
{
return (a=9);
}
int proc(pf p, int a, int b)
{
return ((*p)(a, b));
}

Guys please help me out ...this program is returning 9 as output how it is possible? bcoz pf is defined as taking 2 variables of type int and returning an int..but in this program i mentioned only a function fun with single argument.so as i think program must show error but it is providing a output 9.can someone tell me how it is possible?????????


In c there is no strict checking in compilation time it means that u can pass 1 value during the function calling time or at receiving time function parameter once time a program has been compiled by compiled so it would run....

int fun(int a)
{
return (a=9); //a is assigned to 9 not compared.
}

proc(fun, 6,6)// it would be changed as proc(address of fun, 6,6)

Address of fun containing the value of a=9

What does proc mean and give me its syntax?