C Programming - Functions - Discussion

Discussion Forum : Functions - Find Output of Program (Q.No. 6)
6.
What will be the output of the program?
#include<stdio.h>
int sumdig(int);
int main()
{
    int a, b;
    a = sumdig(123);
    b = sumdig(123);
    printf("%d, %d\n", a, b);
    return 0;
}
int sumdig(int n)
{
    int s, d;
    if(n!=0)
    {
        d = n%10;
        n = n/10;
        s = d+sumdig(n);
    }
    else
        return 0;
    return s;
}
4, 4
3, 3
6, 6
12, 12
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
51 comments Page 5 of 6.

Ammu said:   8 years ago
step 1: d=123%10==3
n=123/10==12
s=3+sumdig(12)since n==12.
step 2: d=12%10==2
n=12/10==1
s=5(since 3+2)+sumdig(1).
step 3: d=1%10==1
n=n/10==0
s=5+1==6
so s==6.
(7)

Chandu said:   8 years ago
In the above program, they mention printf only once after performing sumdig functions. Therefore, the program prints the output values of sumdig values only.

Hakesh said:   7 years ago
What to do with return 0 statement?

Divya gawande said:   7 years ago
Why in output 6, 6 is two times taken? Please explain in detail.
(2)

Noel said:   7 years ago
I think the sticking point for me and others is once you have d = 1%10.

If it were division, the result would be 0. However, with MODULAR MATH, 1%10 is 1.
(1)

Ram said:   7 years ago
Thanks @Ammu.
(1)

Debjani said:   6 years ago
Why the value of b is 6?
(2)

Deepak Johnson said:   6 years ago
Why the value of b is 6?

Samba sivarao said:   6 years ago
@Hakesh.
Return 0 belongs to else part of the function.
If n=0 then value 0 is returned .

In the program, the value n is not equal to 0.
So, if the condition is executed and there is no work with else part.
So the value of s is returned.

Samba sivarao said:   6 years ago
@Deepak and @Debjani.

As we are calling the same function with same parameter in the main.
That value is assigned to 'b'.

So same operation takes place as 'a'.
And then b also get 6.


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