C Programming - Expressions - Discussion

Hi,

int a=10.
Then pre-decrement perform.
We got --a=9.

Then post increment perform.
We got ++a=11.

Then add two value b=9+11.

int a=10;
b=--a + ++a;.

Output of b is 20 how?

@Team Bi.

int a=2,b=3,c;
a=(b++)+(++b)+a;
c=a>b?a:b;
b=(a++)+(b--)+a;
c=c++*b--

The value of a=11, b=25, c=260.

Answer of c+=(a>0&&a<=10)?++a:a/b;a=50;b=10;c=20;

a=4;
printf("%d",a=a++);
printf("%d",a);

Why the output is always 4? Can anyone explain me?

If a=48, b=13; find a+=b++*5/a++ +b.

@atul

putchar() will print char which is equal to ascii value 5+100=105 ie i..then printf will the value of i and so on.

int a=10;
int b;
b=a++ + ++a + ++a;

printf("%d %d %d %d %d %d",b,a++,a,++a,a--,++a);

OUTPUT:
34 14 15 15 14 15

Please explain?

@Ablaze

The operation inside the printf() statement would be performed from Right to left associativity(as the increment operator has the associativity RTL) and the result is stored in the stack.

As the stack works on LIFO (Last In First Out)concept, the printf statement will print the result in Left to Right Associativity.

Lets say

If a = 10
b=a++ + ++a; --- Evaluated as RTL
b = 11+11 = 22
a = 12 (Results of post increment operation)

printf("%d %d %d %d",b,a++,a,++a);

As the associativity of post increment operator is RTL(Right to left). It will be operated in the same way.

Result will be stored in the stack as -

++a = 13
a= 13
a++ = 13

After this statement the value of the a has incremented to 14.

While printing - The top element of the stack would be printed first.

So ++a which has become 14.

a would have the same value as 14.

And in the stack the last value 13.

So the output in gcc compiler is 22 13 14 14.

What is associative and non-associative?