C Programming - Expressions - Discussion
Discussion Forum : Expressions - Find Output of Program (Q.No. 4)
4.
What will be the output of the program?
#include<stdio.h>
int main()
{
int x=12, y=7, z;
z = x!=4 || y == 2;
printf("z=%d\n", z);
return 0;
}
Answer: Option
Explanation:
Step 1: int x=12, y=7, z; here variable x, y and z are declared as an integer and variable x and y are initialized to 12, 7 respectively.
Step 2: z = x!=4 || y == 2;
becomes z = 12!=4 || 7 == 2;
then z = (condition true) || (condition false); Hence it returns 1. So the value of z=1.
Step 3: printf("z=%d\n", z); Hence the output of the program is "z=1".
Discussion:
12 comments Page 2 of 2.
Rupali said:
1 decade ago
z = x!=4 || y == 2;
in this case when x!=4 is checked, it results TRUE & in the OR condition when the first condition becomes true the other condition is not checked.
Hence,y==2 will not be evaluated.
But ,overall value ,i.e. value of z=1 because the value of TRUE is 1.
in this case when x!=4 is checked, it results TRUE & in the OR condition when the first condition becomes true the other condition is not checked.
Hence,y==2 will not be evaluated.
But ,overall value ,i.e. value of z=1 because the value of TRUE is 1.
Vinothini said:
2 decades ago
z = x!=4 || y == 2;
becomes z = 12!=4 || 7 == 2;
then z = TRUE || FALSE; Hence it returns TRUE. So the value of z=1.
how did you get z=1
becomes z = 12!=4 || 7 == 2;
then z = TRUE || FALSE; Hence it returns TRUE. So the value of z=1.
how did you get z=1
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