C Programming - Expressions - Discussion
Discussion Forum : Expressions - Find Output of Program (Q.No. 1)
1.
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=-3, j=2, k=0, m;
m = ++i && ++j && ++k;
printf("%d, %d, %d, %d\n", i, j, k, m);
return 0;
}
Answer: Option
Explanation:
Step 1: int i=-3, j=2, k=0, m; here variable i, j, k, m are declared as an integer type and variable i, j, k are initialized to -3, 2, 0 respectively.
Step 2: m = ++i && ++j && ++k;
becomes m = -2 && 3 && 1;
becomes m = TRUE && TRUE; Hence this statement becomes TRUE. So it returns '1'(one). Hence m=1.
Step 3: printf("%d, %d, %d, %d\n", i, j, k, m); In the previous step the value of i,j,k are increemented by '1'(one).
Hence the output is "-2, 3, 1, 1".
Discussion:
28 comments Page 2 of 3.
Asim vaniya said:
7 years ago
int i=-3,j=2,k=0,m;
m = ++i && ++j || ++k;
printf("\n i=%d j=%d k=%d m=%d",i,j,k,m);
What is the output of this one?
m = ++i && ++j || ++k;
printf("\n i=%d j=%d k=%d m=%d",i,j,k,m);
What is the output of this one?
RAGHU said:
8 years ago
Output M=0.
Manju said:
8 years ago
What is the value of m?
m=(K++ - K++), when K=7.
m=(K++ - K++), when K=7.
Jav said:
8 years ago
int main()
{
int i=-2, j=3, k=-1,m;
m=++i && ++j && k++;
printf("%d, %d, %d, %d\n", i, j, k, m);
What should be its output? Please explain.
{
int i=-2, j=3, k=-1,m;
m=++i && ++j && k++;
printf("%d, %d, %d, %d\n", i, j, k, m);
What should be its output? Please explain.
Jav said:
8 years ago
@Lokesh Jain.
if i=-2, j=3, k=-1;
m=++i && ++j && k++;
Then output is m=1 i=-1 j=4 k=0.
Here k is post increment so in k++ it have value -1 but at next line, it gets value 0.
And if i=-2, j=3, k=-1;
m=++i && ++j && ++k;
Then output is m=0 i=-1 j=4 k=0.
Here k is pre-increment so, m is 0 because k is false.
The compiler is giving m=1 how is it?
if i=-2, j=3, k=-1;
m=++i && ++j && k++;
Then output is m=1 i=-1 j=4 k=0.
Here k is post increment so in k++ it have value -1 but at next line, it gets value 0.
And if i=-2, j=3, k=-1;
m=++i && ++j && ++k;
Then output is m=0 i=-1 j=4 k=0.
Here k is pre-increment so, m is 0 because k is false.
The compiler is giving m=1 how is it?
Teju said:
8 years ago
@Siri.
AND(&&)operator.
AND(&&)operator.
SanLakshmi said:
1 decade ago
I can't understand the AND operation.. can anyone explain it?..
Raj said:
9 years ago
int main()
{
int i=-3, j=2, k=0, m;
m = ++i ||++j && ++k;
printf("%d, %d, %d, %d\n", i, j, k, m);
return 0;
}
What will be the output?
{
int i=-3, j=2, k=0, m;
m = ++i ||++j && ++k;
printf("%d, %d, %d, %d\n", i, j, k, m);
return 0;
}
What will be the output?
Don said:
9 years ago
M = -2 && 3 && 1;.
How a negative sign becomes true?
How a negative sign becomes true?
Sandhya said:
9 years ago
How m becomes true? Can anyone explain it?
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