C Programming - Expressions - Discussion
Discussion Forum : Expressions - Find Output of Program (Q.No. 9)
9.
What will be the output of the program?
#include<stdio.h>
int main()
{
int i=3;
i = i++;
printf("%d\n", i);
return 0;
}
Discussion:
70 comments Page 3 of 7.
Amolak said:
1 decade ago
@Siraj.
Output will be : 3, 4.
Output will be : 3, 4.
Krishanu said:
1 decade ago
Please run that code the out will be 3.
Sneha naik said:
1 decade ago
@Suraj.
Answers will be 4, 3 in post increment value will be assigned later incremented so j=3 and i=4.
Answers will be 4, 3 in post increment value will be assigned later incremented so j=3 and i=4.
Saurabh said:
1 decade ago
For that question some compiler will give different answer like Dev C++.
Is giving 3 instead of 4 because when a single expression causes the same object to be modified then inspected the behavior is undefined. In this case I = i++;
Here variable I is being modified and then it is being used by the compiler. That's why answer 4 is coming here.
Is giving 3 instead of 4 because when a single expression causes the same object to be modified then inspected the behavior is undefined. In this case I = i++;
Here variable I is being modified and then it is being used by the compiler. That's why answer 4 is coming here.
Mohammad Mohsin said:
10 years ago
Answer must be 3, because post increment operator assigns value first and then incremented.
In DEV CPP while I run above program answer is 3.
In DEV CPP while I run above program answer is 3.
Akanksha said:
10 years ago
Can anyone solve my doubt? What is the output of this?
i = i++ + i++;
printf("%d",i);
i = i++ + i++;
printf("%d",i);
Juber said:
10 years ago
int i = 3;
i = 3+3;
i = 6;
i++;
i = 7;
i++;
i = 8;
Finally i = 8 will be print;
i = 3+3;
i = 6;
i++;
i = 7;
i++;
i = 8;
Finally i = 8 will be print;
Sweety said:
9 years ago
Answer will be 3, not 4. Just compile it on another online compiler. And conceptually also it should be 3.
Karthik said:
9 years ago
I tired this;
#include<stdio.h>
int main()
{
int i=3;
i = i++;
printf("%d\n%d", i,i++);
return 0;
}
______________
The output is
3
4
Can anyone explain how i++ became 3?
#include<stdio.h>
int main()
{
int i=3;
i = i++;
printf("%d\n%d", i,i++);
return 0;
}
______________
The output is
3
4
Can anyone explain how i++ became 3?
Karthik said:
9 years ago
I tried this code in code block and I got the output as 3. But here, the compiler says 4. Why?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers