C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - General Questions (Q.No. 10)
10.
In the following program where is the variable a getting defined and where it is getting declared?
#include<stdio.h>
int main()
{
extern int a;
printf("%d\n", a);
return 0;
}
int a=20;
Answer: Option
Explanation:
- During declaration we tell the datatype of the Variable.
- During definition the value is initialized.
Discussion:
46 comments Page 2 of 5.
Susee said:
1 decade ago
May I know explanation for "return 0"? What it will do?
Kas said:
1 decade ago
@Jyoti mishra.
#include<stdio.h>
main(){
int n;
int row,col;
scanf("%d",&n);
int m=n;
for(row=1;row<=n;row++){
for(col=1;col<=m-row;col++){
printf(" ");
}
for(col=1;col<=row;col++){
printf("* ");
}printf("\n");
}
getch();
}
#include<stdio.h>
main(){
int n;
int row,col;
scanf("%d",&n);
int m=n;
for(row=1;row<=n;row++){
for(col=1;col<=m-row;col++){
printf(" ");
}
for(col=1;col<=row;col++){
printf("* ");
}printf("\n");
}
getch();
}
Lovely said:
10 years ago
extern int a; a is declared (forward referencing) (compiler only gets hint).
int a=20; is the definition (value is initialized).
Then when is the memory allocated to 20 and given a name a?
int a=20; is the definition (value is initialized).
Then when is the memory allocated to 20 and given a name a?
Ramya said:
10 years ago
Will you explain please?
Ajit Darnal said:
1 decade ago
Definition int a=20 ; is outside the main, how it is possible ?
Anusha said:
10 years ago
If we give like this extern int a = 2;
Is it a declaration or definition?
Please can someone explain this?
Is it a declaration or definition?
Please can someone explain this?
Laxmi said:
9 years ago
extern int a=2; it is a definition. Because variable a is initialized to 2 then memory is created for a. That's why we call it as a definition.
Deepak said:
9 years ago
Here, we should declare a=20 above the main function.
Vishu said:
9 years ago
@Prathyusha.
You are right, answer A is corret.
You are right, answer A is corret.
Vishu said:
9 years ago
@Jyoti.
Here is the code.
#include <stdio.h>
int main()
{
int i,j,n;
printf("enter the num:");
scanf("%d",&n);
for(i = 1; i <= n; i++)
{
for(j = 1; j <=n-i ; j++ )
printf(" ");
for(j = 1; j <= i; j++)
printf("* ");
printf("\n");
}
return 0;
}
Here is the code.
#include <stdio.h>
int main()
{
int i,j,n;
printf("enter the num:");
scanf("%d",&n);
for(i = 1; i <= n; i++)
{
for(j = 1; j <=n-i ; j++ )
printf(" ");
for(j = 1; j <= i; j++)
printf("* ");
printf("\n");
}
return 0;
}
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