C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - General Questions (Q.No. 7)
7.
Which of the following is not user defined data type?
| 1 : | |
| 2 : | |
| 3 : | |
Answer: Option
Explanation:
C data types classification are
- Primary data types
- int
- char
- float
- double
- void
- Secondary data types (or) User-defined data type
- Array
- Pointer
- Structure
- Union
- Enum
So, clearly long int l = 2.35; is not User-defined data type.
(i.e.long int l = 2.35; is the answer.)
Discussion:
48 comments Page 5 of 5.
Vineet said:
1 decade ago
can we define : char enum day[sun,mon];
Tanishka said:
1 decade ago
Can any one give the example of Union?
Shiva said:
1 decade ago
Then what is "long int l = 2.35;" data type called ?
Saru said:
1 decade ago
@Vineet
We cannot define: char enum day[sun,mon]
But we can give it as follows:
#include<stdio.h>
int main()
{
enum var {var1='a',var2,var3};
enum num {num1=5,num2,num3};
printf("%c %c %c \n",var1,var2,var3);
printf("%d %d %d",num1,num2,num3);
return 0;
}
Where the output will be:
a b c
5 6 7
Because, enum is a user defined data type. It is a data type by itself. So you cannot declare it with a built in data type.
We cannot define: char enum day[sun,mon]
But we can give it as follows:
#include<stdio.h>
int main()
{
enum var {var1='a',var2,var3};
enum num {num1=5,num2,num3};
printf("%c %c %c \n",var1,var2,var3);
printf("%d %d %d",num1,num2,num3);
return 0;
}
Where the output will be:
a b c
5 6 7
Because, enum is a user defined data type. It is a data type by itself. So you cannot declare it with a built in data type.
Pradeep chandra said:
1 decade ago
Then what about string?
Ayana said:
1 decade ago
String belongs to array. Its array of characters.
Kavitha said:
1 decade ago
What is meant by user defined data type?
Vinita said:
1 decade ago
@Saru.
Does the value of val and num automatically get incremented?
And if val1 was not initialized what value it would have taken ?
Does the value of val and num automatically get incremented?
And if val1 was not initialized what value it would have taken ?
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