C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - General Questions (Q.No. 7)
7.
Which of the following is not user defined data type?
| 1 : | |
| 2 : | |
| 3 : | |
Answer: Option
Explanation:
C data types classification are
- Primary data types
- int
- char
- float
- double
- void
- Secondary data types (or) User-defined data type
- Array
- Pointer
- Structure
- Union
- Enum
So, clearly long int l = 2.35; is not User-defined data type.
(i.e.long int l = 2.35; is the answer.)
Discussion:
48 comments Page 5 of 5.
Padma said:
1 decade ago
Yes kavi but there is a user defined data type. It is not in it.
Kavitha said:
1 decade ago
int float char also not a userdefiend data then why it comes answer is both 1 and 2
Pankaj said:
1 decade ago
#include<stdio.h>
int main()
{
enum var {var1,var2,var3};
enum num {num1=5,num2,num3};
printf("%d %d %d \n",var1,var2,var3);
printf("%d %d %d",num1,num2,num3);
return 0;
}
int main()
{
enum var {var1,var2,var3};
enum num {num1=5,num2,num3};
printf("%d %d %d \n",var1,var2,var3);
printf("%d %d %d",num1,num2,num3);
return 0;
}
Roko said:
1 decade ago
How can we implement it to the programming?
Shriya said:
1 decade ago
Is not enum a user defined data type?
Sirajmuneer said:
1 decade ago
We can store list of items in a single name called enum
synatx:
enum(val1,val2,....valn);
compailer assign val1=0,val1=1 and so on
we can assign directly to the value of enum
val1=50,
second value is generally 51 and third is 52 and so on
synatx:
enum(val1,val2,....valn);
compailer assign val1=0,val1=1 and so on
we can assign directly to the value of enum
val1=50,
second value is generally 51 and third is 52 and so on
Sony said:
1 decade ago
Could you say about enum data type.
Shan_mani said:
1 decade ago
Can you explain the enum operation?
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