C Programming - Declarations and Initializations - Discussion
Discussion Forum : Declarations and Initializations - Find Output of Program (Q.No. 1)
1.
What is the output of the program given below ?
#include<stdio.h>
int main()
{
enum status { pass, fail, atkt};
enum status stud1, stud2, stud3;
stud1 = pass;
stud2 = atkt;
stud3 = fail;
printf("%d, %d, %d\n", stud1, stud2, stud3);
return 0;
}
Answer: Option
Explanation:
enum takes the format like {0,1,2..) so pass=0, fail=1, atkt=2
stud1 = pass (value is 0)
stud2 = atkt (value is 2)
stud3 = fail (value is 1)
Hence it prints 0, 2, 1
Discussion:
57 comments Page 3 of 6.
Mounika said:
9 years ago
How it is 0, 2, 1? Where we are declared with 0, 1, 2. So output should be 0, 1, 2.
Sonu said:
1 decade ago
But while declaring the sequence is ok but in the output why the sequence change ?
Vinod said:
10 years ago
enum status stud1, stud2, stud3;
Can anyone explain this declaration statement?
Can anyone explain this declaration statement?
Anita said:
6 years ago
In this enum is a data type how can we mention? here it starts with 1or0.
Puja said:
9 years ago
When I run this program then it produces the output only 0, 2 not 1. Why?
Pradeep Bhat said:
1 decade ago
I agree with shafi. int can do the work of enum declaration here.
Prema said:
9 years ago
If enum takes value staring from 1 then the output will be D.
Silpa said:
8 years ago
Please tell me anyone. Here what is the meaning of atkt?
Mukund said:
1 decade ago
Well I cant understand this program can anyone help.
Tejas said:
1 decade ago
Please anyone explain me about enumerated data type.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers