C Programming - Control Instructions - Discussion
Discussion Forum : Control Instructions - General Questions (Q.No. 2)
2.
How many times the while loop will get executed if a short int is 2 byte wide?
#include<stdio.h>
int main()
{
int j=1;
while(j <= 255)
{
printf("%c %d\n", j, j);
j++;
}
return 0;
}
Answer: Option
Explanation:
The while(j <= 255) loop will get executed 255 times. The size short int(2 byte wide) does not affect the while() loop.
Discussion:
59 comments Page 3 of 6.
Ahmedation said:
1 decade ago
It will be infinite number of loops truly but if only the variable type was signed/unsigned char.
DEEPak said:
1 decade ago
In question 1, while loop will execute 256 times. 1 time also for false condition. But the body will execute only 255 times only.
Amandeep Kaur said:
1 decade ago
Answer is infinite times, how it will be execute 255 times?
Amol wavare said:
1 decade ago
Answer is finite times. How it will be 256>255?
Pankaj said:
1 decade ago
Its signed so how 255 could be the answer?
Abhishek said:
1 decade ago
char i;
for(i=0;i<255;i++)
{
printf("%c",i);
}
I want to ask that after 255. What will happen? It will go to 0 and continue to run from 1, 2 or will run infinite times?
for(i=0;i<255;i++)
{
printf("%c",i);
}
I want to ask that after 255. What will happen? It will go to 0 and continue to run from 1, 2 or will run infinite times?
Vibhan said:
10 years ago
Sorry friends but get excited 256 because it check while loop at the time when j value is 256. So while statement execute 256 times.
Tara said:
10 years ago
The loop will execute for infinity times, like 0 to 128.
Then -128 to -1 again from 0-128, the loop repeats.
Then -128 to -1 again from 0-128, the loop repeats.
Sowjanya said:
10 years ago
Thank you all for your suggestions.
Vishal zadafiya said:
9 years ago
Loop will execute infinite time because int by default signed ao its range is -127 to 128 first it's execute 1 to 128 then 0 to 127 and again start 1 to 128.
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