C Programming - Complicated Declarations - Discussion
Discussion Forum : Complicated Declarations - Find Output of Program (Q.No. 2)
2.
What will be the output of the program in DOS (Compiler - Turbo C)?
#include<stdio.h>
double i;
int main()
{
(int)(float)(char) i;
printf("%d", sizeof((int)(float)(char)i));
return 0;
}
Answer: Option
Explanation:
Due to the C language is being platform dependent:
In Turbo C (DOS - 16 bit platform), the output will be 2.
But in GCC (Unix/Linux - 32 bit platform), the output will be 4.
In Turbo C (DOS - 16 bit platform), the output will be 2.
But in GCC (Unix/Linux - 32 bit platform), the output will be 4.
Discussion:
19 comments Page 2 of 2.
Suresh said:
1 decade ago
I gets cast to a char, then to a float and finally to an int whose size is then used in sizeof. In Turbo C int is 2 bytes.
Raja said:
2 decades ago
The option does not matches with the answer of the online compiler which is giving the answer as 4.
Why?
Why?
Himanshu said:
1 decade ago
What the meaning of these three declaration... which is consider by compiler... int, char, float?
Archana said:
1 decade ago
But look at the declaration of I globally at the top. What does it signify in the pgm?
Sasi said:
1 decade ago
Can you please explain (int) (float) (char) i this statement?
Naresh said:
10 years ago
Is it possible to convert float (4 bytes) to int (2 bytes)?
Shri said:
1 decade ago
Very good explanation kapilsuman. Kudos to you.
Kaleem said:
1 decade ago
That right way to explain.... weldn kapilsuman
Pavan Kumar said:
9 years ago
What is typecasting?
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