C Programming - Complicated Declarations - Discussion
Discussion Forum : Complicated Declarations - Find Output of Program (Q.No. 3)
3.
What will be the output of the program?
#include<stdio.h>
int main()
{
char huge *near *far *ptr1;
char near *far *huge *ptr2;
char far *huge *near *ptr3;
printf("%d, %d, %d\n", sizeof(**ptr1), sizeof(ptr2), sizeof(*ptr3));
return 0;
}
Discussion:
31 comments Page 3 of 4.
Jayshree said:
10 years ago
I am confused about output can you explain anyone again!
Jaswanth said:
1 decade ago
Any pointer holds 4 bytes of memory in gcc compiler.
Vishwanath said:
3 years ago
Hello, Anyone, please explain the problem solution.
(1)
Nagarjuna said:
1 decade ago
Size of the pointer will take the size is 4 bytes.
Thamil said:
1 decade ago
Need proper clarification regarding this problem.
SRIJAN said:
1 decade ago
Whats the size of near, huge and far pointer ?
(1)
Parth barde said:
7 years ago
Thank you all for explaining the solution.
Vikas said:
1 decade ago
Thanks sowmy its really a good reference.
Mikkawy said:
5 years ago
@Naseeb.
GCC (Gnu Compiler Collection).
GCC (Gnu Compiler Collection).
Khattu said:
1 decade ago
near, far, huge these are deprecated.
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