C Programming - Complicated Declarations - Discussion
Discussion Forum : Complicated Declarations - Find Output of Program (Q.No. 1)
1.
What will be the output of the program?
#include<stdio.h>
int main()
{
char far *near *ptr1;
char far *far *ptr2;
char far *huge *ptr3;
printf("%d, %d, %d\n", sizeof(ptr1), sizeof(ptr2), sizeof(ptr3));
return 0;
}
Discussion:
31 comments Page 2 of 4.
Simran said:
6 years ago
Near ptr has a memory of 2bytes. Far and huge ptr have a memory of 4 bytes. Hence the output is 2, 4, 4.
(1)
Hari said:
1 decade ago
Near ptr has a memory of 2bytes. Far and huge ptr hav a memory of 4 bytes. Hence the output is 2, 4, 4.
Arun yadav said:
8 years ago
It's valid in turbo c.
For GCC there is no such concept of near and far,
For GCC it's 4 4 4.
For GCC there is no such concept of near and far,
For GCC it's 4 4 4.
(1)
Subash said:
1 decade ago
Will any body give me the full bytes details of these type of declarations. ?
Sathish said:
1 decade ago
Any body please give what's the difference between these three declarations.
Saurabh said:
7 years ago
Can you please tell me how to read the below line?
char far *near *ptr1;
char far *near *ptr1;
Prasad said:
1 decade ago
Can anybody provide me link to know about these near and far pointers?
Sam said:
9 years ago
I don't understand the program statements. Please explain me once.
Shashidhar said:
1 decade ago
Can any one say me the difference between these three pointers?
Sureka said:
6 years ago
I am not getting this, please explain me.
(1)
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