C Programming - Bitwise Operators - Discussion

#include<stdio.h>

int main()
{
char c=48;
int i, mask=01;
for(i=1; i<=5; i++)
{
printf("%c", c|mask);
mask = mask<<1;
}
return 0;
}

Please explain above the program.

It is nothing but shifting the binary values to left !! In case if u have a binary number 11001101, after you left shit this binary number by 1 digit, you will have 10011010.. that is, the first digit is removed and a he remaining elements are written and a zero is appended at last...

I cant understand that left shift operation "<<"
Can anyone pls explain me n make me clear

Thanks a lot Sai!! :) :)

Thanks sai.

Well. Thanku.

Here mask means unsigned int i.e no negative values....mask 01 means 32 bit value.it is "00000000000000000000000000000001"
c=48 it is written as "00000000000000000000000000110000"
now "or" operation is performed then value becomes 49,
mask=mask<<1 means it shifts 1 to 1-bit before then it becomes "000000000000000000000000000000010".now do o operation with 32digit binary bit of 48.

Now value becomes 50.again mask=mask<<1 "00000100"(last 8bits)similarly do till for loop fails..then we get values as 49,50,52,56,48....the %c converts int to char thatmeans it prints the ASCII values of these nunbers ASCII of 48=0,49=1,50=2......57=9..replace the values u get o/p as 12480......

Can anyone please explain this. ?

Explanation. Please?

To increment five times in i and multiple by c and i and mask.