C Programming - Bitwise Operators - Discussion

Why it is printing only mask value?

It is supposed to print c|mask, instead it is printing only the value of mask.

At 5th loop mask=01000 and 48 or 01000 gives 64 then how it comes 48 again?

Hi @arun

Here c is assigned 48 so its binary value is 110000
mask is assigned 1 i.e 00000001

So while running the for loop first time
c|mask means bitwise operation is performed so each bit is manupulated

So c|mask gives

00110000
00000001
--------
00110001 = 49

But we are printing using %c so the ascii character corresponding to this is printed

So 1 is printed

then the mask is left shifted so it becomes 00000010
so if we perform or operation we will get 50 which is equal to 2
like this it prints 12345

#include<stdio.h>

int main()
{
char c=48;
int i, mask=01;
for(i=1; i<=5; i++)
{
printf("%c", c|mask);
mask = mask<<1;
}
return 0;
}

Please explain above the program.

Well said. For clearing my confusion.

I cant understand that left shift operation "<<"
Can anyone pls explain me n make me clear

Thanks a lot Sai!! :) :)

Thanks sai.

Well. Thanku.