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C Programming - Bitwise Operators - Discussion

Discussion Forum : Bitwise Operators - Point Out Correct Statements (Q.No. 4)
Bitwise Operators
4.
Which of the following statements are correct about the program? 
#include<stdio.h>

int main()
{
    unsigned int m[] = {0x01, 0x02, 0x04, 0x08, 0x10, 0x20, 0x40, 0x80};
    unsigned char n, i;
    scanf("%d", &n);
    for(i=0; i<=7; i++)
    {
        if(n & m[i])
            printf("yes");
    }
    return 0;
}
It will put OFF all bits that are ON in the number n
It will test whether the individual bits of n are ON or OFF
It will put ON all bits that are OFF in the number n
It will report compilation errors in the if statement.
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
13 comments Page 2 of 2.
Nitesh said:   1 decade ago
ox01= 0*16^1+1*16^0=1

Now( num & ox01 (i.e.1))==will check whthr LSB is set or not

Similarly
ox02 ,ox04,ox08 will check 2ndbit,3rd bit and 4th bit
and then ox10=1*16^1+0*16^0=16
i.e 10000 hence it will check for 5th bit and so on...
like ox80= 8*16^1+0*16^0=128
i.e 1000 0000 it will check for 8th bit..

So code will check set bit upto 8 bit...
Subash said:   1 decade ago
I think & operator is for both off and (on or off).
Neha said:   1 decade ago
Can anybody explain.
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