C Programming - Bitwise Operators - Discussion
Discussion Forum : Bitwise Operators - Find Output of Program (Q.No. 10)
10.
What will be the output of the program?
#include<stdio.h>
int main()
{
printf("%d %d\n", 32<<1, 32<<0);
printf("%d %d\n", 32<<-1, 32<<-0);
printf("%d %d\n", 32>>1, 32>>0);
printf("%d %d\n", 32>>-1, 32>>-0);
return 0;
}
Discussion:
42 comments Page 2 of 5.
Sairam said:
9 years ago
int main()
{
int a = 10, b = 5, c = 5;
int d;
d = b + c == a;
printf("%d", d);
}
Can anyone say answer for this?
{
int a = 10, b = 5, c = 5;
int d;
d = b + c == a;
printf("%d", d);
}
Can anyone say answer for this?
Himani said:
9 years ago
Please, explain 32>>-1 and 32<<-1 in easy way.
Siva said:
1 decade ago
Tell me the value of 60 and ~60 same how? explain now.
Sai said:
8 years ago
Can any one tell me when we are taking 16 bit number & 8 bit number?
Jason said:
8 years ago
The behavior is undefined according to "standard" C. You may interpret -1 as shift into opposite direction ( << -1 is actually >> 1) or you may interpret as (unsigned ) -1.
Ankita said:
7 years ago
How to convert -0 to its 2's complement?
Laxman said:
7 years ago
-1 times shifting is exactly equal to 31 times according to gcc when given variable is intiger type.
Md Wasim Akram said:
7 years ago
In Codeblock GCC Compiler 32 Bit its o/p is;
64 32
16 32
16 32
64 32
But unfortunately, this answer is not available in option.
64 32
16 32
16 32
64 32
But unfortunately, this answer is not available in option.
Animesh said:
7 years ago
I got an output 32 <<-1 = 64 and 32>>-1=16;
Am I right?
Am I right?
Udit said:
6 years ago
Please explain the following in the code.
1. 32>>-0
2. 32<<-0
1. 32>>-0
2. 32<<-0
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