C Programming - Bitwise Operators - Discussion
Discussion Forum : Bitwise Operators - Find Output of Program (Q.No. 12)
12.
What will be the output of the program ?
#include<stdio.h>
int main()
{
int i=4, j=8;
printf("%d, %d, %d\n", i|j&j|i, i|j&&j|i, i^j);
return 0;
}
Discussion:
25 comments Page 2 of 3.
Yasaswini said:
8 years ago
@Sana.
X and y values are defined as constant.
So values don't change.
The answer is 50 60 110.
If it is wrong pls tell me how it comes?
X and y values are defined as constant.
So values don't change.
The answer is 50 60 110.
If it is wrong pls tell me how it comes?
Tarun Ghosh said:
10 years ago
^ this is binary XOR operator. Perform Bit-wise XOR operation Means odd no. of 1 is 1 otherwise 0. Then you will get your answer.
Wikiok said:
1 decade ago
& (bit AND) has in higher precedence than | (bit OR).So
4|8&8|4 == (4| (8&8) | 4) == ((4|8)|4) == (12|4) == 12
4|8&8|4 == (4| (8&8) | 4) == ((4|8)|4) == (12|4) == 12
Rahul said:
1 decade ago
Bitwise & has more precedence comp then bitwise or why you first solve bitwise or please tell me.
Neetu said:
2 decades ago
4= 0100
8= 1000 it will give 4|8 = 1100 & 1100 = 1100 equals to 12
4^8 = 1100 = 12
8= 1000 it will give 4|8 = 1100 & 1100 = 1100 equals to 12
4^8 = 1100 = 12
Roh said:
1 decade ago
Answer is correct but no clear explanation.
So, can someone give detailed explanation?
So, can someone give detailed explanation?
Madhureddy said:
1 decade ago
What vennila said is correct but you should perform & operation rather | operation.
Sudha said:
1 decade ago
@Neetu.
The output is:
51 59 110
The correct or not.
Please anyone tell me.
The output is:
51 59 110
The correct or not.
Please anyone tell me.
Sana said:
1 decade ago
Can any one please tell me if i=4 and j=8 then how i&&j and i||j done?
Aalapini said:
10 years ago
Can some one explain i^j part? The function of ^ operator specifically.
(1)
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