C Programming - Arrays - Discussion
Discussion Forum : Arrays - Find Output of Program (Q.No. 2)
2.
What will be the output of the program ?
#include<stdio.h>
int main()
{
static int a[2][2] = {1, 2, 3, 4};
int i, j;
static int *p[] = {(int*)a, (int*)a+1, (int*)a+2};
for(i=0; i<2; i++)
{
for(j=0; j<2; j++)
{
printf("%d, %d, %d, %d\n", *(*(p+i)+j), *(*(j+p)+i),
*(*(i+p)+j), *(*(p+j)+i));
}
}
return 0;
}
Discussion:
78 comments Page 2 of 8.
Raadhi said:
7 years ago
Thank you @Dilip.
Raadhi said:
7 years ago
Thank you @Dilip.
Raadhi said:
7 years ago
Thank you @Dilip.
Som said:
8 years ago
Hi,
If the variable 'p' in printf statement is replaced by array name 'a', then we get the output as option 'A'.
Could anyone explain this discrepancy?
If the variable 'p' in printf statement is replaced by array name 'a', then we get the output as option 'A'.
Could anyone explain this discrepancy?
Arunsethupathy said:
8 years ago
Thank You @Shweta.
Preethi said:
8 years ago
Nice Explanation @Dilip.
Manoja V. said:
8 years ago
Thank you @Dilip.
Nikhil said:
8 years ago
Please explain this question how the compiler works?
Pradeepa said:
8 years ago
Please, anybody explain this concept and tell the answer for it.
#include
void main()
{
int a[2][2]={{2},{3}};
printf("%d",a[0][0]);
printf("%d",a[0][1]);
printf("%d",a[1][0]);
printf("%d",a[1][1]);
}
#include
void main()
{
int a[2][2]={{2},{3}};
printf("%d",a[0][0]);
printf("%d",a[0][1]);
printf("%d",a[1][0]);
printf("%d",a[1][1]);
}
Priyal said:
8 years ago
Thank you for you answer @Dilip.
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