C Programming - Arrays - Discussion

Here size of an array is assinged to 10 and * has been used to declare pointer funtion so compiler will automatically consider it as an pointer funtion.Here it simply means it is a pointer funtion consisting of 10 elements.

#include<stdio.h>
int main()
{
int a=5;
printf("%d %d %d %d %d", a++, a--, ++a, --a, a);
return 0;
}
when i compile this programme in gcc compiler the output as 4 5 5 5 5
because,programme excute from right to left so
a=5
--a predecrement so --a=4
++a preincrement so ++a=5
a-- postdecrement so actual value is 4,but first a value 5 is printed then it will decrement.
a++ postincrement so actual value is 5,but first a value 4 is printed then it will increment.
but all preincrements and predecrements get final a value 5 and postdecrements & postincrements doesn't change.
then the output is 4 5 5 5 5.

Here [10] is the size of array (as in [], always size of array is represesnted) and *ptr is a pointer pointing the particular array. Means there in the memory, there is an array consisting of 10 blocks of integer type and a pointer is pointing to that particular array.

This array would be accessed by that pointer.

Array size is represented in []ie. , no. Of elements contained in it * represents for a pointer so ptr is a pointer to an array of 10 integers since the return type is specified as int.

int (*ptr) [10].

We can take this a cyclic check and everyone can read it easily by this way.

Start with ptr as it is a pointer go clock wise the next comes as array of size 10 that means ptr is a pointer to an array of 10 and the return type is int so it is finally as:.

ptr is a pointer to an array of 10 integers.

int (*ptr)[10];
ptr is a pointer, but this declaration is called pointer of an array..
Since,(*) this is unary oprator,known as (Astrick);

int(*ptr)[10]

int (*ptr)[10];

Start reading what ever is in brackets 1st ,(ptr is a pointer)
Then go towards left till you hit ; (to an array of 10)
Then go backwards and read what ever is left out, (integers).

int (*arr)[10] /* It refers that arr is a pointer to an array of 10 integers*/
and,
int *arr[10] refers to an array of pointers which can hold the starting address of 10 different array of integer data type....

Here ptr is the pointer for the memory location occupied by array having 10 elements.