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C Programming - Arrays

Exercise : Arrays - Find Output of Program
11.
What will be the output of the program if the array begins 1200 in memory? 
#include<stdio.h>

int main()
{
    int arr[]={2, 3, 4, 1, 6};
    printf("%u, %u, %u\n", arr, &arr[0], &arr);
    return 0;
}
1200, 1202, 1204
1200, 1200, 1200
1200, 1204, 1208
1200, 1202, 1200
Answer: Option
Explanation:

Step 1: int arr[]={2, 3, 4, 1, 6}; The variable arr is declared as an integer array and initialized.

Step 2: printf("%u, %u, %u\n", arr, &arr[0], &arr); Here,

The base address of the array is 1200.

=> arr, &arr is pointing to the base address of the array arr.

=> &arr[0] is pointing to the address of the first element array arr. (ie. base address)

Hence the output of the program is 1200, 1200, 1200

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