Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
Answer: Option
Explanation:
External radius = 4 cm,
Internal radius = 3 cm.
| Volume of iron |
|
||||||
|
|||||||
| = 462 cm3. |
cm3
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
Discussion:
61 comments Page 7 of 7.
Jasir said:
2 hours ago
Given, Outer radius=4cm(from d/2)..
Inner radius = outer radius - thickness:4 - 1 = 3 cm.
Volume = π*(R^2-r^2)*h.
22/7*(16-9)*21.
462 cm^3.
Weight= mass * density.
462 * 8= 3696 gm % 1000 = 3.696kg.
Inner radius = outer radius - thickness:4 - 1 = 3 cm.
Volume = π*(R^2-r^2)*h.
22/7*(16-9)*21.
462 cm^3.
Weight= mass * density.
462 * 8= 3696 gm % 1000 = 3.696kg.
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