Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
60 comments Page 5 of 6.

Dhana reddy said:   8 years ago
Why 4^2 -3^2? Please explain this step.

Krishna said:   1 decade ago
Why external radius is 4cm how is it ?

Shivani said:   1 decade ago
Why there is need to multiply by 22/7?

Nagi said:   9 years ago
Why diameter is converted into radius?

S.Vijay said:   1 decade ago
Tell me the formula of this problem?

Lavanya said:   8 years ago
Thank you, well explained @Dhinesh.

Akanksha said:   1 decade ago
How the internal radius comes ?

Junaid said:   8 years ago
Why is the internal radius 3cm?

Ajay said:   8 years ago
Could you explain me about pi?

Pema said:   4 years ago
Why cant it be =pi * 3^2 * 21?
(1)


Post your comments here:

Your comments will be displayed after verification.