Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
60 comments Page 3 of 6.

Roney said:   6 years ago
@Nazim.

From both side the 1cm will be deducted.
so dia = 6cm radius 3cm.
(5)

Sandeep said:   1 decade ago
Because external diameter is 8cm then.

External radius is 8/2=4cm.

Thuru said:   9 years ago
I don't understand this.

Is there any easy way to understand this?

Sai dileep said:   9 years ago
What is the formula for calculating the volume of this problem?

Nagi said:   9 years ago
Please anyone say why we are taking radius instead of diameter?

Rahul said:   6 years ago
There is a formula for hollow sphere 3.14 (R^2-r^2)h.

Rohan said:   7 years ago
How did you find out the DENSITY = 8? Please explain.

Tejas said:   1 decade ago
What is iron pipe here?

Is it volume of cylinder?

Dinesh Reddy said:   3 years ago
Can anyone explain this answer once again deeply?
(1)

VINU said:   1 decade ago
Why subtract external radius to internal radius?


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