Aptitude - Volume and Surface Area - Discussion

Discussion Forum : Volume and Surface Area - General Questions (Q.No. 5)
5.
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
3.6 kg
3.696 kg
36 kg
36.9 kg
Answer: Option
Explanation:

External radius = 4 cm,

Internal radius = 3 cm.

Volume of iron
= 22 x [(4)2 - (3)2] x 21 cm3
7
= 22 x 7 x 1 x 21 cm3
7
= 462 cm3.

Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.

Discussion:
61 comments Page 3 of 7.

Nagi said:   10 years ago
Please anyone say why we are taking radius instead of diameter?

Indranath said:   9 years ago
Why not (4-3)^2?

Dhana reddy said:   9 years ago
Why 4^2 -3^2? Please explain this step.

Lavanya said:   9 years ago
Thank you, well explained @Dhinesh.

Albin Antony said:   1 decade ago
Volume = base area * height.

For calculating, base area of the given hollow cylinder, we should remove the area containing thickness from the original.

So (pi * 4^2) - (pi*3^2) = pi* (4^2 - 3^2) = Effective base area.

Mritunjay said:   9 years ago
1dm=how many metre

Rohan said:   9 years ago
How did you find out the DENSITY = 8? Please explain.

CHINMAYE said:   8 years ago
@Rohan.

It's given in the question that iron weighs 8 g/cm3. It's nothing but a density.

Rahul said:   7 years ago
There is a formula for hollow sphere 3.14 (R^2-r^2)h.

Sunil said:   7 years ago
Why 4 square minus 3 square equals to 7 * 1.


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