Aptitude - Volume and Surface Area - Discussion
Discussion Forum : Volume and Surface Area - General Questions (Q.No. 9)
9.
A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
Answer: Option
Explanation:
| Area of the wet surface | = [2(lb + bh + lh) - lb] |
| = 2(bh + lh) + lb | |
| = [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2 | |
| = 49 m2. |
Discussion:
40 comments Page 3 of 4.
Naveen said:
1 decade ago
Water is only at 1.25 m depth. Then why I have to take whole 6 m to calculate the wet surface?
Fainaz said:
1 decade ago
Because all the answers are in "meter square". If its cylinder then it will be in meter cube.
Kailash singhania said:
8 years ago
@Sandya.
1m and 25 cm is actually converted into meter which will be 1.25 m.
1m and 25 cm is actually converted into meter which will be 1.25 m.
Ankit rai said:
8 years ago
But only the wet area is taken as cuboid so why do we subtract lb?
(1)
Chirag Barad said:
10 years ago
Because there is ask only about wet surface, not total surface.
Tejas said:
1 decade ago
@Rajesh.
l means length, b means bridth and h means height.
l means length, b means bridth and h means height.
Rani said:
1 decade ago
Why lb is subtracted from total surface area of cistern?
Jeet said:
1 decade ago
2lh+2bh+lb what is this formula for I mean area of what?
Vishnu said:
1 decade ago
Its because the other side (top surface) won't get wet.
Piyush said:
10 years ago
How do we know upper part not containing height?
(1)
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