Aptitude - Volume and Surface Area
Exercise : Volume and Surface Area - General Questions
- Volume and Surface Area - Formulas
- Volume and Surface Area - General Questions
- Volume and Surface Area - Data Sufficiency 1
- Volume and Surface Area - Data Sufficiency 2
11.
The curved surface area of a cylindrical pillar is 264 m2 and its volume is 924 m3. Find the ratio of its diameter to its height.
Answer: Option
Explanation:
r2h |
= | 924 | r = |
![]() |
924 | x 2 | ![]() |
= 7 m. |
2 rh |
264 | 264 |
And, 2 rh = 264 h = |
![]() |
264 x | 7 | x | 1 | x | 1 | ![]() |
= 6m. |
| 22 | 2 | 7 |
Required ratio = |
2r | = | 14 | = 7 : 3. |
| h | 6 |
12.
A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:
Answer: Option
Explanation:
Let the thickness of the bottom be x cm.
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
320 x 250 x (110 - x) = 8000 x 1000
(110 - x) = |
8000 x 1000 | = 100 |
| 320 x 250 |
x = 10 cm = 1 dm.
13.
What is the total surface area of a right circular cone of height 14 cm and base radius 7 cm?
Answer: Option
Explanation:
h = 14 cm, r = 7 cm.
So, l = (7)2 + (14)2 = 245 = 75 cm.
Total surface area |
= rl + r2 |
|||||||||
|
||||||||||
| = [154(5 + 1)] cm2 | ||||||||||
| = (154 x 3.236) cm2 | ||||||||||
| = 498.35 cm2. |
14.
A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
Answer: Option
Explanation:
Volume of the large cube = (33 + 43 + 53) = 216 cm3.
Let the edge of the large cube be a.
So, a3 = 216
a = 6 cm.
Required ratio = |
![]() |
6 x (32 + 42 + 52) | ![]() |
= | 50 | = 25 : 18. |
| 6 x 62 | 36 |
15.
How many bricks, each measuring 25 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
Answer: Option
Explanation:
| Number of bricks = | Volume of the wall | = | ![]() |
800 x 600 x 22.5 | ![]() |
= 6400. |
| Volume of 1 brick | 25 x 11.25 x 6 |
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r2h

Required ratio =