Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 9)
9.
A does 80% of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
Answer: Option
Explanation:
Whole work is done by A in | ![]() |
20 x | 5 | ![]() |
= 25 days. |
4 |
Now, | ![]() |
1 - | 4 | ![]() |
i.e., | 1 | work is done by A and B in 3 days. |
5 | 5 |
Whole work will be done by A and B in (3 x 5) = 15 days.
A's 1 day's work = | 1 | , (A + B)'s 1 day's work = | 1 | . |
25 | 15 |
![]() |
![]() |
1 | - | 1 | ![]() |
= | 4 | = | 2 | . |
15 | 25 | 150 | 75 |
So, B alone would do the work in | 75 | = 37 | 1 | days. |
2 | 2 |
Discussion:
164 comments Page 3 of 17.
Nanny said:
1 decade ago
Thank you bhaskar, you done great job, keep it up.
Prathap said:
1 decade ago
Bhaskar and rajendra you both are explained very well. Thanks.
Vinoth said:
1 decade ago
@baskar your explations were very nice thank you so much.
Charu said:
1 decade ago
Thanks Bhasker, Ganesh and Mini... Keep up the good work!!! cheers
Suganya said:
1 decade ago
Simple method:.
A's one day work 80/20=4%.
A's three days work 12%.
The remaining work is only done by B in that three days=20%-12%=8%.
B's one days work=8/3%.
B completes 100% work in.
8/3% * x =100%.
So x=75/2=37.5.
A's one day work 80/20=4%.
A's three days work 12%.
The remaining work is only done by B in that three days=20%-12%=8%.
B's one days work=8/3%.
B completes 100% work in.
8/3% * x =100%.
So x=75/2=37.5.
Chandana said:
1 decade ago
80/100 = 4/5.
5/4*20 = 25days.
A and B completes the remaining work in 3 days i.e.,
3*5 = 15days.
A's 1 days work is 1/25.
B's 1 days work is 1/15.
Therefore, b's one days work will be,
1/5-1/25 = 5-3 / 75 = 2/75 i.e 75/2 will give us 37.5, So B alone will complete the entire work in 37.5 OR 37 1/2 :)
5/4*20 = 25days.
A and B completes the remaining work in 3 days i.e.,
3*5 = 15days.
A's 1 days work is 1/25.
B's 1 days work is 1/15.
Therefore, b's one days work will be,
1/5-1/25 = 5-3 / 75 = 2/75 i.e 75/2 will give us 37.5, So B alone will complete the entire work in 37.5 OR 37 1/2 :)
Alle chandra shekar said:
1 decade ago
Please tell me short cut method.
$ha$ha said:
1 decade ago
Let total work=100%.
A do 80% work = 20 days.
A's 1 day work= 1/20 * 80% i:e 1/20 * 80/100 = 2/50.
Now,Remaining work is 100-80=20%.
So, A and B together complete remaining work i.e 20% in 3days.
Therefore A and B 1 day work = 1/3 * 20% i:e 1/3 * 20/100= 1/15.
Now, B's alone 1 day work is,
A+B=1/15
2/50+B=1/15
B=1/15 - 2/50 = 10-6/150 = 2/75.
Now, B alone can complete work in 75/2 days i.e option C.
A do 80% work = 20 days.
A's 1 day work= 1/20 * 80% i:e 1/20 * 80/100 = 2/50.
Now,Remaining work is 100-80=20%.
So, A and B together complete remaining work i.e 20% in 3days.
Therefore A and B 1 day work = 1/3 * 20% i:e 1/3 * 20/100= 1/15.
Now, B's alone 1 day work is,
A+B=1/15
2/50+B=1/15
B=1/15 - 2/50 = 10-6/150 = 2/75.
Now, B alone can complete work in 75/2 days i.e option C.
Yogesh said:
1 decade ago
My method:
A's 1% work done time = 80/20 = 4%.
Means in 1 day a completes 4%......(1).
Now,
A+B 1 day work = 20/3.
B work = 20/3 - 4/1 = 8/3.
B work in 1 day = 8/3 ---- (2).
So now,
For 100% work by B is:
8/3*1/100 = 300/8 = 37.5 days. work
Answer..(:
A's 1% work done time = 80/20 = 4%.
Means in 1 day a completes 4%......(1).
Now,
A+B 1 day work = 20/3.
B work = 20/3 - 4/1 = 8/3.
B work in 1 day = 8/3 ---- (2).
So now,
For 100% work by B is:
8/3*1/100 = 300/8 = 37.5 days. work
Answer..(:
Ajith said:
1 decade ago
1) 100*20/80 =25.
2) Total work done in 25 days.
3) Remaining work finished in 5 days.
4) If A&B work together 3*5=15.
5) A's one days work 1/25.
6) A+B one days work 1/15.
7) 1/15 - 1/25 = 4/150= 2/75.
8) So B alone would do the work in 75/2= 37 1/2.
2) Total work done in 25 days.
3) Remaining work finished in 5 days.
4) If A&B work together 3*5=15.
5) A's one days work 1/25.
6) A+B one days work 1/15.
7) 1/15 - 1/25 = 4/150= 2/75.
8) So B alone would do the work in 75/2= 37 1/2.
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