Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 15)
15.
10 women can complete a work in 7 days and 10 children take 14 days to complete the work. How many days will 5 women and 10 children take to complete the work?
Answer: Option
Explanation:
| 1 woman's 1 day's work = | 1 |
| 70 |
| 1 child's 1 day's work = | 1 |
| 140 |
| (5 women + 10 children)'s day's work = |  |
5 | + | 10 |  |
= | |
1 | + | 1 | |
= | 1 |
| 70 | 140 | 14 | 14 | 7 |
5 women and 10 children will complete the work in 7 days.
Discussion:
47 comments Page 3 of 5.
R_pandya said:
10 years ago
Take one women's one day's work = x;
One child's one day's work = y;
10 women can complete the work in 7 days.
So 10x = 1/7.
Similarly 10y = 1/14.
Now take this value in the equation for 5 women and 10 children's work.
5x+10y = 5(1/70)+1/14 = 1/7.
So the total work done in 7 days.
One child's one day's work = y;
10 women can complete the work in 7 days.
So 10x = 1/7.
Similarly 10y = 1/14.
Now take this value in the equation for 5 women and 10 children's work.
5x+10y = 5(1/70)+1/14 = 1/7.
So the total work done in 7 days.
Priya said:
1 decade ago
How to use LCM method for this problem please explain?
Sai krupa said:
1 decade ago
Its always better to take LCM for the total times which gives the total amount of work. So then solve the sum its so simple.
Shiva said:
1 decade ago
10 children 14 days.
20 children 7 days.
=> 1w = 2c.
=> 10c = 5w.
=> 5w+10c = 5w+5w = 10W.
So 10w complete in 7 days given in question.
20 children 7 days.
=> 1w = 2c.
=> 10c = 5w.
=> 5w+10c = 5w+5w = 10W.
So 10w complete in 7 days given in question.
RANJAN said:
1 decade ago
10 WOMEN CAN DO THE WORK IN 7 DAYS.
THEN 5 WOMEN CAN DO THE WORK IN 14 DAYS.
AND 10 CHILDREN CAN DO THE WORK IN 14 DAYS.
SO 5 WOMEN+10 CHILDREN CAN DO THE WORK IN 14*14/14+14 = 7 DAYS.
THEN 5 WOMEN CAN DO THE WORK IN 14 DAYS.
AND 10 CHILDREN CAN DO THE WORK IN 14 DAYS.
SO 5 WOMEN+10 CHILDREN CAN DO THE WORK IN 14*14/14+14 = 7 DAYS.
Deepak Patgar said:
1 decade ago
10 women need 7 days, so 5 women need 14 days.
10 children need 14 days.
So if 5 women and 10 children work together for 14 days they will complete the work twice. To complete it once they will need 14/2 = 7 days.
10 children need 14 days.
So if 5 women and 10 children work together for 14 days they will complete the work twice. To complete it once they will need 14/2 = 7 days.
Rox said:
1 decade ago
10 women in 7 days.
5 women(A) in 14 days.
A = (1/14).
10 child(B) in 14 days(given).
B = (1/14).
A+B = (1/14+1/14) = 2/14 = 1/7.
That is 7 days.
5 women(A) in 14 days.
A = (1/14).
10 child(B) in 14 days(given).
B = (1/14).
A+B = (1/14+1/14) = 2/14 = 1/7.
That is 7 days.
Medha Bhatnagar said:
1 decade ago
One more way to do this prob.
5* (1/70) +10* (1/140) =2/14=1/7=7 days.
5* (1/70) +10* (1/140) =2/14=1/7=7 days.
Disha said:
1 decade ago
Love your way to solve the problem. Swamy.
Superb brain.
Superb brain.
Ravi said:
1 decade ago
10 women in 7 days.then v can alsov say 5 women in 14 days.
also 10 children in 14 days.
therfore 1women=2 children.
Now 5 women and 10 children are 20 children(as 1women =2 children).
As 10children in 10days therefore 20 children in 7 days.
also 10 children in 14 days.
therfore 1women=2 children.
Now 5 women and 10 children are 20 children(as 1women =2 children).
As 10children in 10days therefore 20 children in 7 days.
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