Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 20)
20.
Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi. The number of days taken by Tanya to do the same piece of work is:
15
16
18
25
Answer: Option
Explanation:

Ratio of times taken by Sakshi and Tanya = 125 : 100 = 5 : 4.

Suppose Tanya takes x days to do the work.

5 : 4 :: 20 : x    x = 4 x 20
5

x = 16 days.

Hence, Tanya takes 16 days to complete the work.

Discussion:
94 comments Page 8 of 10.

Mahesh Neupane said:   8 years ago
Sakshi efficiency is 1/20.
Tanya Efficiency is 25% more than Sakshi.
So, 1/20+(25%of1/20)=16%.

Subhasis said:   10 years ago
What if I think tanaya takes 75 days and sakshi takes 100 days, then answer will be 15 days.

Sai said:   1 decade ago
Tanya's one day work =(1/20 + 25% of 1/20) = 1/20+1/80 = 1/16 once explain the equation.

Abyzy said:   6 months ago
(SAKSHI) 125%=20,
(TANYA) 100%= x,
125*x = 20*100,
x = (20*100)/125,
x = 16 days.
(4)

Ayush said:   9 years ago
@All.

Refer the post of Kamlesh It's quite easy to understand, Thanks @Kamlesh.

Cheenu said:   9 years ago
Can anybody explain this how x = 16 has come from this equation 5:4::20:x?

Devi prasad said:   10 years ago
Their is mixed view of this question but we got both the answer correctly.

Sujith said:   1 decade ago
Tanya is 25% more efficient than Sakshi. Then ratio should be 3:4 rite ?.

Chandu said:   1 decade ago
5 : 4 :: 20 : x

Can you explain the meaning of the above line?

Sahithikarne said:   8 years ago
25% of 20 is 5 then the answer is 20-5=15. But how it is 16?


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