Aptitude - Time and Work - Discussion
Discussion Forum : Time and Work - General Questions (Q.No. 8)
8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
Answer: Option
Explanation:
(A + B)'s 1 day's work = | 1 |
10 |
C's 1 day's work = | 1 |
50 |
(A + B + C)'s 1 day's work = | ![]() |
1 | + | 1 | ![]() |
= | 6 | = | 3 | . .... (i) |
10 | 50 | 50 | 25 |
A's 1 day's work = (B + C)'s 1 day's work .... (ii)
From (i) and (ii), we get: 2 x (A's 1 day's work) = | 3 |
25 |
![]() |
3 | . |
50 |
![]() |
![]() |
1 | - | 3 | ![]() |
= | 2 | = | 1 | . |
10 | 50 | 50 | 25 |
So, B alone could do the work in 25 days.
Discussion:
146 comments Page 15 of 15.
Shweta said:
6 years ago
Thank you @Awoke your method was easy.
Shweta said:
6 years ago
Thank you @Sneha you made the given solution easier to understand.
Naheed said:
5 years ago
Thank you @Awoke your method was so easy.
Thilak said:
5 years ago
How come 1/10, Can you please explain it?
Ravi said:
4 years ago
Thanks @Sneha.
You explained it well.
You explained it well.
Naveen said:
4 years ago
A = B+C( A work is equal to B and C work)---> 1
A+ B = 10 days (A and B can do a work in 10 days)--> 2
C=50 days( C alone do work in 50 days)----> 3.
Let's assume work as a 50 parts.(take LCM of 10,50).
A+B=5parts(A anb B can do 5 parts a day work)--> 4.
C=1 part(C can do work 1 part a day I,e 50 parts 50 days)---> 5.
From equation 1: A=B+C
A = B + 1(from eq 5).
3 + 2 = 5(from eq 4).
B = 2 parts.
50 parts of work can do in 25 days. B can do parts a day.
A+ B = 10 days (A and B can do a work in 10 days)--> 2
C=50 days( C alone do work in 50 days)----> 3.
Let's assume work as a 50 parts.(take LCM of 10,50).
A+B=5parts(A anb B can do 5 parts a day work)--> 4.
C=1 part(C can do work 1 part a day I,e 50 parts 50 days)---> 5.
From equation 1: A=B+C
A = B + 1(from eq 5).
3 + 2 = 5(from eq 4).
B = 2 parts.
50 parts of work can do in 25 days. B can do parts a day.
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