Aptitude - Time and Work - Discussion

Discussion Forum : Time and Work - General Questions (Q.No. 8)
8.
A can do a certain work in the same time in which B and C together can do it. If A and B together could do it in 10 days and C alone in 50 days, then B alone could do it in:
15 days
20 days
25 days
30 days
Answer: Option
Explanation:

(A + B)'s 1 day's work = 1
10

C's 1 day's work = 1
50

(A + B + C)'s 1 day's work = 1 + 1 = 6 = 3 . .... (i)
10 50 50 25

A's 1 day's work = (B + C)'s 1 day's work .... (ii)

From (i) and (ii), we get: 2 x (A's 1 day's work) = 3
25

A's 1 day's work = 3 .
50

B's 1 day's work 1 - 3 = 2 = 1 .
10 50 50 25

So, B alone could do the work in 25 days.

Discussion:
146 comments Page 15 of 15.

Shweta said:   6 years ago
Thank you @Awoke your method was easy.

Shweta said:   6 years ago
Thank you @Sneha you made the given solution easier to understand.

Naheed said:   5 years ago
Thank you @Awoke your method was so easy.

Thilak said:   5 years ago
How come 1/10, Can you please explain it?

Ravi said:   4 years ago
Thanks @Sneha.

You explained it well.

Naveen said:   4 years ago
A = B+C( A work is equal to B and C work)---> 1
A+ B = 10 days (A and B can do a work in 10 days)--> 2
C=50 days( C alone do work in 50 days)----> 3.

Let's assume work as a 50 parts.(take LCM of 10,50).

A+B=5parts(A anb B can do 5 parts a day work)--> 4.
C=1 part(C can do work 1 part a day I,e 50 parts 50 days)---> 5.

From equation 1: A=B+C
A = B + 1(from eq 5).
3 + 2 = 5(from eq 4).
B = 2 parts.
50 parts of work can do in 25 days. B can do parts a day.


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