Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 3)
3.
The least perfect square, which is divisible by each of 21, 36 and 66 is:
Answer: Option
Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 22 x 32 x 72 x 112 = 213444
Discussion:
80 comments Page 3 of 8.
Malakarsidda said:
1 decade ago
How to sole this step 2772 = 2 x 2 x 3 x 3 x 7 x 11?
Prashant said:
1 decade ago
For LCM 21, 36 & 66:
3/21 36 66.
2/7 12 22.
3/7. 6. 11.
2/7. 2. 11.
7. 1. 11.
3 x 3 x 2 x 2 x 7 x 11 = 213444.
3/21 36 66.
2/7 12 22.
3/7. 6. 11.
2/7. 2. 11.
7. 1. 11.
3 x 3 x 2 x 2 x 7 x 11 = 213444.
Tejaswini said:
1 decade ago
How it is possible?
Raju said:
1 decade ago
2x2x3x3x7x11 = 2772.
Here all are pair numbers but 7 & 11 are single numbers that's why we multiple by 7 & 11 again.
Here all are pair numbers but 7 & 11 are single numbers that's why we multiple by 7 & 11 again.
Santosh said:
1 decade ago
Take that example.
Take LCM of that numbers.
LCM (21, 36, 66) = 2*3*7*2*6*11==> 2*3*7*2*3*11==> 2^2*3^2*11*7.
To make above as perfect square we multiply with 11 and 7.
So (2^2*3^2*7*11)*7*11 = 213444.
Take LCM of that numbers.
LCM (21, 36, 66) = 2*3*7*2*6*11==> 2*3*7*2*3*11==> 2^2*3^2*11*7.
To make above as perfect square we multiply with 11 and 7.
So (2^2*3^2*7*11)*7*11 = 213444.
Ravinesh kumar said:
10 years ago
I am not satisfy with this solution.
Ravinesh kumar said:
10 years ago
This solution is not satisfactory.
Yassmin said:
9 years ago
A square number is when you times a number or numbers to itself.
Harish said:
9 years ago
Is there any other method to solve the question? If yes please tell me the trick.
Ganesh Policherla said:
9 years ago
We can get the perfect square must multiplied 7 x 11.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers