Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 3)
3.
The least perfect square, which is divisible by each of 21, 36 and 66 is:
Answer: Option
Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 22 x 32 x 72 x 112 = 213444
Discussion:
80 comments Page 3 of 8.
Ganesh Policherla said:
9 years ago
We can get the perfect square must multiplied 7 x 11.
Harish said:
9 years ago
Is there any other method to solve the question? If yes please tell me the trick.
Yassmin said:
9 years ago
A square number is when you times a number or numbers to itself.
Ravinesh kumar said:
10 years ago
This solution is not satisfactory.
Ravinesh kumar said:
10 years ago
I am not satisfy with this solution.
Gaurav said:
10 years ago
Can't understand how 7*11 is considered and what about 2*2 & 3*3?
YASH said:
10 years ago
We divide all answer option by 21, 36, 66 and find a option.
Raaj said:
1 decade ago
How the answer come like this?
Sheikh Muhammad Ammar said:
1 decade ago
I think according to maths rule 7 & 11 must be multiplied on both ends.
Hence 2^2*3^2*7*11*(7*11) = 2772*7*11.
= 2^2*3^2*7^2*11^2 = 213444.
Hence 2^2*3^2*7*11*(7*11) = 2772*7*11.
= 2^2*3^2*7^2*11^2 = 213444.
Rahul Gupta said:
1 decade ago
This solution is very confusing, kindly explain in simple manner.
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