Aptitude - Square Root and Cube Root - Discussion

Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 3)
3.
The least perfect square, which is divisible by each of 21, 36 and 66 is:
213444
214344
214434
231444
Answer: Option
Explanation:

L.C.M. of 21, 36, 66 = 2772.

Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11

To make it a perfect square, it must be multiplied by 7 x 11.

So, required number = 22 x 32 x 72 x 112 = 213444

Discussion:
80 comments Page 2 of 8.

Sowjanya said:   1 decade ago
It is very difficult to divide all the options with the given numbers. It will take more time it is better to go to the LCM/HCF methods. Its very simple that multiplying 7 and 11 to make all the number a perfect square and multiply all the numbers we will get answers.

Sneha said:   1 decade ago
First least num that is divisible by 21,36,66 by taking l.c.m ,

We get 2772,
by taking factors 2772=2*2*3*3*7*11
as we have find least perfect square
we need to multiply with 7*11,so we can get perfect sq. near to 2772

So the soltn is 2*2*3*3*7*7*11*11 = 213444.

Swasthik said:   1 decade ago
Hi friends,

Here I will tell you the simple method to solve.

Just add alternative digit from the given answer eg: 213444.

Now add 2+3+4 = 9.

1+4+4 = 9.

Then deduct 9-9=0 if you get answer is 0. That means it is divisible by given number. :).

Sandip said:   1 decade ago
2 / 21 36 66
--------------------
2 / 7 18 66
---------------------
3 / 7 9 33
---------------------
3 / 7 3 11
----------------------
/ 7 1 11


2*2*3*3*7*11= 2772


pls see this way solve the problem

Achutha reddy said:   1 decade ago
21 = 3*7.

36 = 3*3*2*2.

66 = 11*3*2.

Means our must be divisible by 2, 3, 7, 11.

**All numbers are evens, so 2 is satisfied.

***3 is common factor for 21, 36, 66 so it is also satisfied.

So you have to check for 7 and 11.

i.e 213444.

S.manikandan said:   1 decade ago
21----7*3.
36-----3*3*2*2.
66-------3*2*11.

So here, [7*3*3*3*2*2*3*2*11].

As per the rule we multiply 7*11*3*3*2*2 = 2772.

Here both 3 and 2 are doubles. For perfect square all should be double. So multiple with 7*11 we get 213444.

Santosh said:   1 decade ago
Take that example.

Take LCM of that numbers.

LCM (21, 36, 66) = 2*3*7*2*6*11==> 2*3*7*2*3*11==> 2^2*3^2*11*7.

To make above as perfect square we multiply with 11 and 7.

So (2^2*3^2*7*11)*7*11 = 213444.

Pooja said:   1 decade ago
Hi @Swasthik.

According to your method 214434 is also a right answer.

Because 214434 now add alternative nos ie 2+4+3 = 9.

1+4+4 = 9 and when we deduct its 0 so it is also a right answer.

Sudarshana said:   1 decade ago
I found the answer correct when I tried to divide each of the options by 21, 36, 66. And only opt. A was found to divide with all three without any fraction.

Is it the write method ?

Shudhakar kumar gupta said:   8 years ago
7and 11 multiply because according to question make perfect square 2 and 3 is left square but 7 and 11 not a perfect square so 7and 11 make a perfect square so multiply 7 and 11.


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