Aptitude - Square Root and Cube Root - Discussion
Discussion Forum : Square Root and Cube Root - General Questions (Q.No. 9)
9.
The square root of (7 + 35) (7 - 35) is
Answer: Option
Explanation:
| (7 + 35)(7 - 35) | = | (7)2 - (35)2 | = 49 - 45 = 4 = 2. |
Discussion:
24 comments Page 3 of 3.
Sree said:
4 years ago
How 45 came?
(2)
Shahil Solanki said:
3 years ago
@Sweety and @Sree
(3√5)^2.
= 3^2 *(√5)^2,
= 9 * 5,
= 45.
(3√5)^2.
= 3^2 *(√5)^2,
= 9 * 5,
= 45.
(1)
Ranjith Ragava said:
3 years ago
(7+3√5)(7-3√5).
(a+b)(a-b)=a^2-b^2,
= (7)^2-(3√5)^2,
= (49)-(3^2√5^2),
= 49-(9)(5),
= 49-45,
= 4.
(a+b)(a-b)=a^2-b^2,
= (7)^2-(3√5)^2,
= (49)-(3^2√5^2),
= 49-(9)(5),
= 49-45,
= 4.
(3)
Devendra said:
2 years ago
To find the square root of the expression (7 + 3√5) (7 - 3√5), we can simplify it using the difference of squares formula.
Let's denote the expression as A = (7 + 3√5) (7 - 3√5).
Using the difference of squares formula, we have:
A = (7 + 3√5) (7 - 3√5)
= (7)^2 - (3√5)^2,
= 49 - 9(√5)^2,
= 49 - 9(5),
= 49 - 45,
= 4.
Therefore, the √ of (7 + 3√5) (7 - 3√5) is √4 = 2.
Let's denote the expression as A = (7 + 3√5) (7 - 3√5).
Using the difference of squares formula, we have:
A = (7 + 3√5) (7 - 3√5)
= (7)^2 - (3√5)^2,
= 49 - 9(√5)^2,
= 49 - 9(5),
= 49 - 45,
= 4.
Therefore, the √ of (7 + 3√5) (7 - 3√5) is √4 = 2.
(2)
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